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How much weight transfer do we get by Torque ?


susser

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Oright;

The torque delivered to the back wheels at maximum torque will occur at probably 70% or so of V Max if a fairly normal torqe curve for a fairly average engine is considered, I would guess.

The reaction to this torque will be demonstrated at weight transfer to the rear.

So how much is it ??

Bring it on.

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Formulas for g force & weight transfer:

 

drive wheel torque = flywheel torque x first gear x final drive x 0.85

 

wheel thrust = drive wheel torque / rolling radius

 

g = wheel thrust / weight

 

weight transfer = weight x cg height / wheelbase x g

 

lateral acceleration = 1.227 x raduis / time^2

 

lateral weight transfer = weight x cg height / wheel track x g

 

hope this helps *biggrin*

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Wonky

Don't think we need all that squit.

Max torque times gearbox ratio (1:1 ?) (Ignore 5th) times diff ratio = ACWM as viewed from the nearside.

Therefore force at front wheels is normal front axle weight minus CWM divided by horizontal distance from rear wheel centre to centre of contact patch of front wheels.

My guess is that it's not insignificant.

S'pose that's why dragsters shove a long nose on the nail the fuel tank to. (Lots of CWM ).

I'm off home for a drink.

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Blast and damnation *mad*

I was going to do some sums tonight, but I've been preparing the boat for a long voyage (all the way to Gellesdon) and forgot.

Now I've got on the home brew and I forget how to do it. *confused*

I'll get another couple of pints in and forget that I forgot.

Smashin. *wink*

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