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Ballast resistors - more than one type, I just discovered


anthonym

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#BDR Ballast resistors generally

This post/entry is summarised here:

If a ballast resistor is installed in the circuit to the battery instead of the ignition circuit, it is serving a different purpose. To clarify the roles and placements of different types of resistors in automotive electrical systems read on:

### Ballast Resistor in Ignition Circuit:

1. **Purpose**: Manage voltage to the ignition coil.

2. **Placement**: Between the ignition switch and the ignition coil in the ignition circuit.

3. **Function**: Reduces voltage to the ignition coil during normal operation to prevent overheating, and allows full voltage during starting for a stronger spark.

### Resistor in Battery Circuit:

1. **Purpose**: Could serve various functions depending on its specific application within the battery circuit.

2. **Common Uses**:

   - **Voltage Regulation**: To manage and stabilise voltage supplied to various electrical components.

   - **Current Limiting**: To limit the current flow to protect sensitive components from high current spikes.

   - **Load Distribution**: To balance the electrical load across different circuits.

### Potential Different Uses:

1. **Voltage Regulator Circuit**:

   - **Purpose**: To ensure a stable voltage supply to sensitive electronic components.

   - **Placement**: In series with the battery supply to the component needing regulated voltage.

2. **Current Limiting Resistor**:

   - **Purpose**: To limit the amount of current that can flow into a circuit or component.

   - **Placement**: In series with the battery or power supply line to the component.

3. **Load Resistor**:

   - **Purpose**: To simulate a load in the circuit for testing or to ensure proper operation of certain components.

   - **Placement**: Parallel to the component or circuit where the load is required.

### Conclusion:

While a ballast resistor in the ignition circuit specifically manages the voltage to the ignition coil, a resistor installed in the battery circuit could serve a variety of purposes depending on the specific application. These purposes include voltage regulation, current limiting, and load distribution, and their placement would differ based on their intended function.

### Important Points:

- **Ballast Resistor for Ignition**: Always placed in the ignition circuit between the ignition switch and coil. But see in the comments below about the starting circuit NOT going via the ballast resistor, for starting it supplies 12v direct without going via the ballast resistor. 

- **Other Resistors in Battery Circuit**: Serve different roles such as voltage regulation or current limiting, and are placed accordingly in the electrical system, commonly as in my car to stop the alternator hitting the main circuits with excessive charge.

 

#BDR Ballast resistor in the ignition circuit

A ballast resistor is an electrical component used in some ignition systems to help manage the voltage supplied to the ignition coil, thereby optimising the performance of the spark plugs during engine starting and running. Here’s a detailed explanation of how a ballast resistor functions and why it is used:

### Purpose and Function of a Ballast Resistor:

1. **Voltage Management**:

   - **During Normal Operation**: The ballast resistor reduces the voltage that reaches the ignition coil when the engine is running normally. This helps prevent the coil from overheating and extends its lifespan.

   - **During Starting**: When the engine is cranking, the ballast resistor is bypassed, allowing the full battery voltage to reach the ignition coil. This provides a stronger spark to the spark plugs, which is particularly important for starting the engine.

### How It Works:

1. **Normal Running Condition**:

   - When the engine is running, the electrical system typically operates at around 12-14 volts. The ballast resistor is connected in series with the ignition coil, reducing the voltage that the coil receives to around 6-9 volts.

   - This reduced voltage is sufficient to produce a strong enough spark for normal engine operation while protecting the coil from excessive heat and prolonging its life.

2. **Starting Condition**:

   - During engine start-up, the starter motor draws a significant amount of current, which can cause a temporary drop in battery voltage.

   - To ensure a strong spark during this critical time, a bypass circuit is often used. This circuit bypasses the ballast resistor, allowing the full battery voltage (which might be around 10-12 volts during cranking) to be supplied directly to the ignition coil.

   - The higher voltage increases the coil's output, producing a more powerful spark at the spark plugs, which helps to ignite the fuel-air mixture more effectively, making it easier to start the engine.

### Benefits:

1. **Enhanced Starting Performance**:

   - By bypassing the ballast resistor during starting, the ignition system provides a stronger spark, which is especially helpful in cold conditions or with a cold engine, where starting might otherwise be more difficult.

2. **Protection and Longevity**:

   - During normal operation, the ballast resistor reduces the voltage to the ignition coil, preventing overheating and premature failure. This ensures that the coil operates within its optimal voltage range and lasts longer.

### Typical Setup:

- **Ballast Resistor**: A resistor connected in series with the ignition coil.

- **Bypass Circuit**: Often implemented using a relay or an extra terminal on the starter solenoid that temporarily bypasses the ballast resistor during engine start-up.

### Example:

In a typical ignition system with a ballast resistor:

- When the ignition key is turned to the "start" position, a bypass circuit activates, sending full battery voltage to the ignition coil.

- Once the engine starts and the key is released to the "run" position, the ballast resistor comes back into play, reducing the voltage to the coil to its normal operating level.

### Conclusion:

A ballast resistor is a crucial component in some ignition systems that helps balance the need for high voltage during starting with the need to protect the ignition coil during normal operation. By reducing the voltage during normal running conditions, it extends the life of the coil, and by allowing full voltage during starting, it ensures a strong spark for easier engine ignition.

==========================================

Personally I am still trying to understand how reducing the voltage gets a stronger spark. See below in the comments where it is explained to me.

Here's a ballast resistor in the main battery cutoff circuitimage.thumb.png.7da3787e4a0c7204a7e016af366b9d69.png

and here's one included in the sale supply of a new coil designed to be used with a ballast resistor:

image.thumb.png.0efeb4f0956ccfdc88286bd97b3a7270.png

 

 

 

12 Comments


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Anthony, it is not the reduced voltage that produces a stronger spark.  It is the increased voltage during starting, when the ballast resistor is bypassed, that produces the stronger spark

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ahhhh!! zo. it's the exclusion of the ballast resistor from the starting circuit that allows the full 12v during starting whereas the running circuit to the coil has its voltage reduced to 9v by the ballast resistor with the purpose of protecting (extending the life of) the coil.

Right?

which also means any circuit with a ballast resistor MUST have that ballast resistor exclusion not as an option but obligatorily

thanks for patience with this bear of small brain

Edited by anthonym
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Yes, except the ballast resistor is not excluded from the circuit just that an additional non-resistor supply is introduced while the starter is working

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that a "no" or "not quite" 🙂 ok so not "excluded", but what?

"an additional non-resistor supply is introduced while the starter is working"

"bridged", "ignored", "skipped", "bypassed"? 

"bypassed"?  edit: While editing the a.i. descriptions in my o.p. I see it uses "bypass".

In any case another/further wire with 12v supply is used..? So we have one wire via ballast resistor and one (from the starting circuit) not via the ballast resistor?

"excluded" is the word used I found when first googling, granted not very informative as to how.

I have edited the o.p. to check for any hallucinations (false content from an a.i.).

Edited by anthonym
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If you're using a ballast resistor, you must have a corresponding coil designed for a ballast resistor. In the 60's and 70's manufacturers fitted ballast and non ballast coils to their cars so you need to be sure on what you have, especially as people can fit the wrong parts by accident in the last 50 to 60 years.

Normally the coil is designed for receiving a 12v supply, magic inside the coil (windings) does stuff so that when the points trigger a big fat spark is created.

When you're cranking you don't get 12v at the coil as the starter takes lots of power and due to chemistry the battery will only be producing 9v. Often 9v is enough for the coil to create a spark, but its not a big fat powerful spark. Engines can then struggle to start.

Ballast resistor coils are designed to run on 9v. You therefore need a ballast resistor to convert the 12v battery supply to 9v for normal running to the coil. When the engine is cranking the ballast resistor will reduce the 9v the battery is producing to 6v. So you have the same problem as above. The solution is a second wire from the starter solenoid. When ever the solenoid is open, so the starter is spinning you also directly feed the coil with as many volts as the battery can manage via this second wire. This means you've now got 9v at the coil and the big fat spark. As soon as the starter stops spinning the additional feed stops so the ballast resistor is being used and you still get 9v.

 

If you fit a ballast resistor to a normal coil you'll not get a big fat spark as the magic inside the coil isn't working as designed. You may still get a spark but you'll get running problems. When you go to crank you'll be getting 6v and you'll be very lucky to get the engine to start without a jump pack / additional battery.

 

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To aid the thought process, this is the starter relay (picture stolen from ebay & found using the google search term "xflow starter solenoid" )

image.png.d94bc91632d7e0bd74430d443db9b32b.png

on it you can see the terminal that is powered whilst the starter signal has power, which is also allowing the starter motor connector to receive power from the battery feed. 

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"magic inside the coil (windings) does stuff so that when the points trigger a big fat spark is created."

that sounds like the idea of a "step-up" transformer

and an "aha":

"Ballast resistor coils are designed to run on 9v. You therefore need a ballast resistor to convert the 12v battery supply to 9v for normal running to the coil."

Having just fitted a new starter (several times, long story) there was no sign of any signal connection.

 

edit: note to self: I read that modern coils draw about 4 amps while the points are closed. Either 12V across a 3-ohm primary coil or 6-9V across 1.5 ohms in a ballast coil. Either way, somewhere in the 4-6 amp range while the car is running... so when cranking? 

Interesting chatter on stackexchange: https://electronics.stackexchange.com/questions/291128/power-output-of-ignition-coil it's capacitor type behaviour.. fill and release

Edited by anthonym
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10 minutes ago, anthonym said:

Having just fitted a new starter (several times, long story) there was no sign of any signal connection.

3 hours ago, Miker7 said:

The solution is a second wire from the starter solenoid. When ever the solenoid is open, so the starter is spinning you also directly feed the coil with as many volts as the battery can manage via this second wire.

Jonathan

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What sort of starter to you have? If its a starter with a built in solenoid (known as pre-engaged as the starter throws the gear towards the flywheel and once engaged with the flywheel it automatically applies the power) then your wire could be there (its been a while since i looked at these). If its a Bendix starter ( this just has a power connector, it spins the starter that twists the gear to connect with the flywheel) then it would be from the solenoid.

Why can't you use a wire directly connected to the starter power supply? no idea, i don't do electronics but i'd guess things like power spikes and upsetting the mythical Lucas god of darkness causing him anger and releasing the special smoke of expensive repairs.

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It's a Brise pre-engaged (solenoid wire 10cm from primary), that replaces a "standard" pre-engaged (solenoid wire 1mm from primary). I have pics (somewhere not far away). 

New kit may (might!) arrive tomorrow so we will/might see. Said god being willing and the dhl demon being distracted

edit: connecting the solenoid to the coil seems nice and simple where an ignition ballast resistor is in play... also avoids hanging me upside down under the dash to wire something; try to avoid that these days.

I was wondering about this too https://electronics.stackexchange.com/questions/291128/power-output-of-ignition-coil it seems the coil collects and releases.. but I had thought it was a step-up pair of coils.. (bit long since school physics)

Edited by anthonym
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